Question

如圖：AB=AC，∠A=50°，點(diǎn)O是△ABC內(nèi)一點(diǎn)，且∠OBC=∠ACO，則∠BOC=  .

Answer 1

115°

由題, AB=AC，∠A=50°，所以∠ABC=∠ACB, ∠A +∠ABC+∠ACB =180°，故∠ACB=65°,在△BOC中, ∠O +∠OBC+∠OCB =180°，而∠OBC=∠ACO,所以∠O +∠OBC+∠ACO =∠ACB +∠O =180°，∠O=115°.
試題分析：等腰三角形的底角相等,三角形內(nèi)角和為180°,由題, AB=AC，∠A=50°，所以∠ABC=∠ACB, ∠A +∠ABC+∠ACB =180°，故∠ACB=65°,在△BOC中, ∠O +∠OBC+∠OCB =180°，而∠OBC=∠ACO,所以∠O +∠OBC+∠ACO =∠ACB +∠O =180°，∠O=115°.