Question

比較大小：log₂0.3     2^0..3 （填＞或＜）．

Answer 1

【答案】分析：根據(jù)對(duì)數(shù)函數(shù)和指數(shù)函數(shù)的性質(zhì)可直接比較出大小．
解答：解：∵2＞1，0.3＜1
∴l(xiāng)og₂^0.3＜0
∵2^0.3＞0
∴l(xiāng)og₂0.3＜2^0..3 
故答案為＜
點(diǎn)評(píng)：本題主要考查了數(shù)值的大小比較．解題的關(guān)鍵是要利用對(duì)數(shù)和指數(shù)函數(shù)的性質(zhì)得出log₂^0.3＜0，2^0.3＞0問(wèn)題就迎刃而解了．